5-x^2=10+4x^2

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Solution for 5-x^2=10+4x^2 equation: 



5-x^2=10+4x^2

We move all terms to the left:

5-x^2-(10+4x^2)=0

We add all the numbers together, and all the variables

-1x^2-(10+4x^2)+5=0

We get rid of parentheses

-1x^2-4x^2-10+5=0

We add all the numbers together, and all the variables

-5x^2-5=0

a = -5; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-5)·(-5)
Δ = -100
Delta is less than zero, so there is no solution for the equation

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